Regex.replace

You're seeing just the function replace, go back to Regex module for more information.
Link to this function

replace(regex, string, replacement, options \\ [])

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Specs

replace(t(), String.t(), String.t() | (... -> String.t()), [term()]) ::
  String.t()

Receives a regex, a binary and a replacement, returns a new binary where all matches are replaced by the replacement.

The replacement can be either a string or a function. The string is used as a replacement for every match and it allows specific captures to be accessed via \N or \g{N}, where N is the capture. In case \0 is used, the whole match is inserted. Note that in regexes the backslash needs to be escaped, hence in practice you'll need to use \\N and \\g{N}.

When the replacement is a function, the function may have arity N where each argument maps to a capture, with the first argument being the whole match. If the function expects more arguments than captures found, the remaining arguments will receive "".

Options

  • :global - when false, replaces only the first occurrence (defaults to true)

Examples

iex> Regex.replace(~r/d/, "abc", "d")
"abc"

iex> Regex.replace(~r/b/, "abc", "d")
"adc"

iex> Regex.replace(~r/b/, "abc", "[\\0]")
"a[b]c"

iex> Regex.replace(~r/a(b|d)c/, "abcadc", "[\\1]")
"[b][d]"

iex> Regex.replace(~r/\.(\d)$/, "500.5", ".\\g{1}0")
"500.50"

iex> Regex.replace(~r/a(b|d)c/, "abcadc", fn _, x -> "[#{x}]" end)
"[b][d]"

iex> Regex.replace(~r/a/, "abcadc", "A", global: false)
"Abcadc"